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## 5(cos 96 + i sin 96), 5(cos 216 + i sin 216) and 5(cos 336 + i sin 336).

SOLUTION: Find the cube roots of 125(cos 288 + i sin 288).

My work so far:

5(cos 96 + i sin 96),

5(cos 216 + i sin 216) and

5(cos 336 + i sin 336).

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-> SOLUTION: Find the cube roots of 125(cos 288 + i sin 288).

My work so far:

5(cos 96 + i sin 96),

5(cos 216 + i sin 216) and

5(cos 336 + i sin 336).

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Please help with precalc problems! : cheatatmathhomework – According to De Moivre's theorem, the nth roots of a complex number r(cos θ + isin θ) are given by:. r 1/n (cos((θ + 2πk)/n) + isin((θ + 2πk)/n)). for integer k from 0 to n − 1. So in this case, n = 4. Thus, the four roots are of the form (256) 1/4 (cos((280° + 360°k)/4) + isin((280° + 360°k)/4)), or: z*1* = 4(cos(280°/4) + isin(280°/4)) = 4(cos(70°) + isin(70°))Question 1024127: Find the cube roots of 125(cos 288° + i sin 288°). Answer by Alan3354(67397) ( Show Source ): You can put this solution on YOUR website!Calculate the fifth root of numbers. 5th root calculator. List of roots for resulting answers 1 through 10. Free online calculators for radicals, exponents, math, fractions, factoring, plane geometry, solid geometry, algebra, finance and more. Calculator roots.

SOLUTION: Find the cube roots of 125(cos 288° + i sin 288°). – 288 + 720 = 1008. 1008 / 3 = 336 (or -24, same thing) 5(cos -24 + i sin -24) is the third cube root.—-You could go on adding 360 then dividing the new sum by 3, but you would find that you are simply repeating the same angles (trig functions have a cycle of 360) In this way, you always find 2 square root, three cube roots, four 4th roots, etc.Find the cube roots of 125(cos 288° + i sin 288°). Correct answer: r = 5 If it is known that a person will select any one page between the pages numbered 125 and 384, find the probability of choosing the page numbered 252 or 253. TrianglesQuestion: Find The Cube Roots Of 125(cos 288° + I Sin 288°) This problem has been solved! See the answer. Find the cube roots of 125(cos 288° + i sin 288°) Expert Answer 100% (1 rating) Previous question Next question Get more help from Chegg. Solve it with our pre-calculus problem solver and calculator

Fifth Roots Calculator – What are the cube roots of 125(cos 288 + i sin 288). View the step-by-step solution to: Question What are the cube roots of 125(cos 288° + i sin 288°). Top Answer. Hi. The cube roots are: 4.56-2.03i (principal root)-0.52+4.97i -4.04-2.93i. Explanation: Hello. I calculate the cubic roots of the complex number as I show it in the attached fileUsing thr De Moivre's formula we get (125 (cos 288° + i sin 288°))^ (1/3)=125^ (1/3) (cos 288°/3 + i sin 288°/3)=5 (cos 96° + i sin 96°)= (approximately)-0.5+4.97i. Need a fast expert's response?Find the cube roots of 125(cos 288° + i sin 288°). Help me please; 2.Find the cube roots of 27(cos 279° + i sin 279°). Help me please; 3.Write the complex number in the form a + bi. 8(cos 30° + i sin 30°) Help me please; 4.Express the complex number in trigonometric form. -2 Help me please; 5.