source : yahoo.com
How many moles of K+ are present in a 343 mL of a 1.27 M solution of K3PO4?
Notice that every mole of this molecule contains 3 moles of the potassium ion K+. Remember this for the end of the problem…
0.343L K3PO4 x 1.27M K3PO4 = 0.43561 moles K3PO4
Now we use that conversion factor from the beginning:
0.43561 moles K3PO4 x (3 moles K+ / 1 mole K3PO4) = 1.308361 moles K+
Round to the correct significant figures:
1.31 moles K+
Source(s): PS: I think you meant to put this in Chemistry instead of Math.
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