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How many moles of K+ are present in a 343 mL of a 1.27 M solution of K3PO4?

source : yahoo.com

How many moles of K+ are present in a 343 mL of a 1.27 M solution of K3PO4?

K3PO4

Notice that every mole of this molecule contains 3 moles of the potassium ion K+. Remember this for the end of the problem…

0.343L K3PO4 x 1.27M K3PO4 = 0.43561 moles K3PO4

Now we use that conversion factor from the beginning:

0.43561 moles K3PO4 x (3 moles K+ / 1 mole K3PO4) = 1.308361 moles K+

Round to the correct significant figures:

1.31 moles K+

Source(s): PS: I think you meant to put this in Chemistry instead of Math.

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SOLVED:Calculate the number of moles of each ion

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