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## How many oxygen atoms are contained in 2.74g of Al2(SO4)3?

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Study Chem 133 Exam 2 Flashcards | Quizlet – How many oxygen atoms are contained in 2.74 g of Al2(SO4)3? e ionic equation for any acid reacting with any base is: H+(aq) + OH-(aq) –> H2O(l) The H2SO4 provides the H+ ions.Moles of Aluminium Sulphate contains 0.24 moles of Oxygen So 2×10−2 Moles is the answer How many sulphur atoms are associated in colloidal sol?Problem #1: How many atoms of chlorine are in 16.50 g of iron(III) chloride? 5.80 x 1023 molecules times 3 C atoms per molecule = 1.74 x 1024 <—answer for (a). Bonus Problem: A sample of HNO3 contains twice as many atoms as there are atoms in 6.840 g of Al2(SO4)3. Calculate the mass of…

How many moles of aluminium sulphate, Al2(SO4) 3 will contain 0.24… – How many moles of copper are contained in 525 g of copper? Solution: The molar mass of copper from the periodic table is 63.55 g/mol. Avogadro's number tells us how many calcium atoms are in a mole of calcium, but the given information in this example is grams of calcium.Question: How Many Oxygen Atoms Are Contained In 2.74 G Of Al2(SO4)3? The Answer Is 5.79×1022. I Need Steps To Figure Out Why Though. I Use Avagrados Number, But Am Getting The Wrong Answer.How many atoms of carbon are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)3 is 233.99 g/mol. Determine the mass of oxygen in a 7.2-g sample of Al2(SO4)3. chemistry 110. what combinations of Zn, Al, ZnSO4 and Al2(SO4)3 would you make to illustrate that Zn is less active than…

ChemTeam: Using Avogadro's Number in Calculations – Problems 1-10 – Question 3. How many atoms are present in a (i) H2S molecule and (ii) P043- ion? Answer: The ions which contain more than one atoms (same kind or may be of different kind) and behave (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)…How many Li atoms are contained in 97.9kg of Li. Oxygen cannot be broken into two atoms unless it is an oxygen compound of oxygen.(a) The Rutherford atom has a small, positively charged nucleus, so most α particles will pass terms of how closely the α particles pass by the nucleus undeflected and the angle of deflection. A molecule of oxygen, O2, contains two oxygen atoms; the subscript 2 in the formula must be used…

**Converting between Moles, Atoms, and Molecules (Part 2)** – This is the second part to converting between

moles, atoms, and molecules.

We're going to do some more practice problems but if you

haven't seen the first video, check that out first and then come and watch this. How many

molecules in 0.63 moles of molecules? Now we're talking about molecules here, before

we were talking about atoms but it doesn't matter what we're talking about because there

is always 602 hexillion things in a mole. So if we have a mole of molecules, a mole

of jellybeans, a mole of coins, a mole of atoms, they all have 602 hexillion things

in them and the process we go through is exactly the same. Okay, so just to think through this

as we did before, we're talking about 0.63 moles of molecules. What would we do if we

had 0.63 dozen molecules? There are 12 things in a dozen so we do 0.63 times 12 which is

the number of things in one dozen okay? That kind of makes intuitive sense. We're not talking

about dozens here though we're talking about moles so we want to multiply this by the number

of things in one mole. Let's rewrite this in scientific notation, 602 hexillion as 6.02

x 10^23. We're going to put it in the calculator like this: 0.63*(6.02E23) and get 3.7926E23

as an answer. The first thing let's do is write this in regular scientific notation,

3.7926 x 10^23, and now let's use significant figures to round this since calculators don't

round. We have two significant figures here, the zero doesn't count, we have three significant

figures here so we're going to round this to two significant figures, the smaller of

the two. We keep the 3 and we look at the 7 and then next door to see if we round up

or keep it the same, it's a 9 and higher than 5 so we're going to round up. So we're going

to do 3.8 x 10^23 molecules. And this is our answer here and as I always say, please keep

in mind that this is just a shorthand abbreviation for this super long number. This isn't some

weird Martian number, it's just an abbreviation for this number with all the zeros and you

can totally write this out with all the zeros if it makes you feel better. We'll put this

up here to remind ourselves what the answer is and now let's use conversion factors to

solve this problem in case you have to do that. We are going to start with 0.63 moles

and we're going to want to multiply that by a conversion factor that's going to get rid

of the moles okay? So we're going to use this relationship here, we're going to put moles

on the bottom. So I'm going to put 1 mole here, we're talking about 602 hexillion things

so I'm going to do 6.02 x 10^23 molecules up here. Moles on the top and moles on the

bottom, cancel them out. The math here is going to be 0.63 times 6.02 x 10^23 divided

by 1. Dividing it by 1 doesn't really change anything so the only math that we're really

doing is 0.63 times 6.02 x 10^23, it's exactly what we did up here but again if you want

to type this in with a whole fraction, 0.63*(6.02E23/1), the answer is exactly the same and if we round

it using significant figures we get this number of molecules in 0.63 moles of molecules. Let's

do one more. How many moles is 3.9 x 10^20 Magnesium atoms? Okay, this number here is

not a scary Martian number, it's actually a real number, let's think about what we do

if we were talking about dozens instead of moles. We would take this and we would divide

it by 12 because there are 12 things in a dozen. We want to know how many this 12 goes

into this number, okay? It's intuitive to divide this number by 12 but instead we're

talking about moles so we're going to want to divide this by 602 hexillion. Now let's

put these numbers into scientific notation, (3.9 x 10^20)/(6.02 x 10^23). Put that into

the calculator like this, (3.9E20)/(6.02E23), and we're going to get this as our final answer.

Let's put it into scientific notation, 6.478405316 x 10^-4, which means 10 to the negative 4th,

and now let's use significant figures to round this. There are two significant figures here

and three significant figures here so we'll round this to two numbers, 6.4, you look next

door to the 7 to see if we round up or keep it the same, it's a 7 so we round up, we're

going to do 6.5 x 10 ^-4 moles. That is our answer there and here very quickly is how

we would do this problem using conversion factors. We would start with 3.9 x 10^20 atoms

and we would multiply that by a conversion factor that gets rid of atoms. So 1 mole on

top, 6.02 x 10^23 atoms down here, the atoms cancel out on the top and on the bottom, and

the math that we do is 3.9 x 10^20 times 1 divided by 6.02 x 10^23, this one doesn't

make much of a difference, all we're really doing is this divided by this which is the

math that I did up here. Or you can type this into your calculator like this and get the

same answer, (3.9E20)*(1/6.02E23)=6.478405316E-4. And just once again, keep in mind that this

10^-4 isn't some creepy Martian number but we're doing 6.5 and moving the decimal back

four. And if we wanted to take this out of scientific notation, it would be 0.00065 moles.

You can make this look like a real number as well. So that is how we can convert back

and forth between moles and the number of atoms or molecules we have. .