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If i = sqr. root of -1, which point shows the location of 5 - 2i on the plane?

source : yahoo.com

If i = sqr. root of -1, which point shows the location of 5 – 2i on the plane?

I can’t show you what the “plane”/ graph looks like, but I can tell you that point A is at the coordinate

( – 2 , 5 ), point B is at the coordinate ( 0 , 3 ), point C is at the coordinate ( 3 , 0 ), and point D is at the coordinate ( 5 , – 2 ).

A. point A

B. point B

C. point C

D. point D

sqr. root = square root

Please answer some of my following or previous questions about other math problems! best answer = 10 points

PS. Showing how you got your answer (your work) makes you more likely to win the best answer.

Which point shows the location of 5 - 2i on the - inmoh.net

Which point shows the location of 5 – 2i on the – inmoh.net – Which point shows the location of 5 – 2i on the complex plane? iuse IMAP for your emails. Though you didn't say how many email accounts or hown SingleHop private key of course but when you run a check on if you would read the post in fulloriginal CEO and founder of Arvixe is still as a CEO fpr Arvixe and his name.On the complex plane, it's is almost like a normal coordinate plane except the y-axis is the imaginary line. So to find 5 -2i, we start at the origin and move 5 units to the right and 2 units down. So the answer is C. Hope this helps!The complex number z = 1+2i is represented by the diagram below. The number is represented by the point P whose coordinates is (1,2). The modulus is the length of the line OP which can be founded by either Pythagorean theorem or the formula given above.

#Which point shows the location of 5 – 2i on the complex plane – And "cos θ + i sin θ" is often shortened to "cis θ", so:. x + iy = r cis θ. cis is just shorthand for cos θ + i sin θ. So we can write: 3 + 4i = 5 cis 0.927. In some subjects, like electronics, "cis" is used a lot! Summary. The complex plane is a plane with: real numbers running left-right andSal shows how to plot various numbers on the complex plane. number our real part is the negative 2 and then our imaginary part is a positive 2 and so that right over there in the complex plane is the point negative 2 plus 2i let's do a few more of these so 5 plus 2i once again real part is 5 imaginary part is 2 and we're done let's do two2.5 The point at in nity By de nition theextended complex plane = C[f1g. That is, we have one point at in nity to be thought of in a limiting sense described as follows. A sequence of points fz nggoes to in nity if jz njgoes to in nity. This \point at in nity" is approached in any direction we go. All of the sequences shown in the gure below are

#Which point shows the location of 5 - 2i on the complex plane

Conjugate and Modulus – onlinemath4all – Start studying Performing Operations with Complex Numbers. Learn vocabulary, terms, and more with flashcards, games, and other study tools.distance between the origin (0, 0) and the point (a, b) in the complex plane. For two points in the complex plane, the distance between the points is the modulus of the Find the distance between the points 2 + 3i and 5 − 2i in the complex plane The distance is d = ˚32 + (−5)2 = ˚34 ≈ 5.83 units as shown in the figure below. −1I can't show you what the "plane"/ graph looks like, but I can tell you that point A is at the coordinate ( – 2 , 5 ), point B is at the coordinate ( 0 , 3 ), point C is at the coordinate ( 3 , 0 ), and point D is at the coordinate ( 5 , – 2 ). A. point A B. point B C. point C D. point D sqr. root = square root Please answer some of my following or previous questions about other math problems

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