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## Survey the Question

Let’s search the problem for clues as to what it will be testing, as this will help shift our minds to think about what type of math knowledge we’ll use to solve this question. Pay attention to any words that sound math-specific and anything special about what the numbers look like, and mark them on our paper.

We want to multiply two numbers together and look at what numbers are in the units and tens places, which will involve things we’ve learned about Integers.

## What Do We Know?

Let’s carefully read through the question and make a list of the things that we know.

We will multiply a \$-digit number by a \$-digit number
We want to know that product’s sum of its units and tens digits

## Develop a Plan

Let’s attack this problem with a top-down approach. We want to know the sum of the units and tens digits of the product of the numbers 5{,}278·67{,}066\$. There is one solution readily available to us: we could just multiply the numbers together to get the units and tens digits of the product. That does seem like a time-consuming process, especially if our calculator can’t handle such a large product (like, say, the measly GRE calculator provided to us on test day). So let’s try to find another more clever approach to solving this question.

We might remember from when we first learned long multiplication that the units digit of a product is only determined by the units digits of the numbers being multiplied. Also, the tens digit of a product is determined by the units and tens digits of the numbers being multiplied. If we’re curious about why this is, then let’s feel free to look at it in more depth. Otherwise we can just go ahead and solve this question.

## Concept Refresher – Units and Tens Digits for Multiplication

Since we only care about the units and tens digits, perhaps we would be better off looking at numbers specifically based upon their digits, so let’s split one of the numbers up by its digits. We know that each digit represents a factor of \$, so let’s work on splitting up one of the numbers by writing it as the sum of factors of \$. It doesn’t matter which number we do this for, so we’ll arbitrarily select 5{,}278\$. So let’s first write it as the sum of factors of \$:

\$5{,}278 = 8 + 70 + 200 + 5{,}000 + 20{,}000 + 700{,}000\$\$

Now let’s write out the product that we’re looking for using this:

\$5{,}278·67{,}066 = 67{,}066·(8 + 70 + 200 + 5{,}000 + 20{,}000 + 700{,}000)\$\$

And we know that we can use distribution to rewrite this as the sum of multiple products, by distributing the {,}066\$ inside the parentheses.

\$5{,}278·67{,}066 = 67{,}066·8 + 67{,}066·70 + 67{,}066·200 + …\$\$

We know that when we multiply two numbers together, any [scrape_url:1] source : {source_domain}

## Solve the Question

So we know that we only need to use the tens and units digits in this multiplication to get the tens and units digits of the product, so let’s select the tens and units digits of the two numbers and multiply them together.

\$·66 = 5{,}148\$\$

So the units and tens digits are \$ and \$. Since +8=12\$, the sum of the units and tens digits is \$, and the correct answer is A, \$.

## What Did We Learn

An important lesson to learn from this problem is that we did NOT have to do the entire product just to find the sum of the units and tens digits. So now we know that for future products where we only want to know the units and tens digits, we can just ignore anything beyond the tens digit.

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Have questions? Leave a comment or send us an email at [email protected]. The distance between (x, 2) and (0,6) is 5 units. What is – The distance between #(x, 2)# and #(0,6)# is #5# units. What is the value of #x#? Algebra Radicals and Geometry Connections Distance Formula. 1 Answer Konstantinos Michailidis Aug 16, 2016 The distance between the two points is. #d=sqrt((x-0)^2+(2-6)^2)=sqrt(x^2+16)# Hence . #sqrt(x^2+16)=5# #x^2+16=25# #x^2=9# #x=+-3#Thrust-specific fuel consumption (TSFC) is the fuel efficiency of an engine design with respect to thrust output. TSFC may also be thought of as fuel consumption (grams/second) per unit of thrust (kilonewtons, or kN). It is thus thrust-specific, meaning that the fuel consumption is divided by the thrust.What is the value of x? 12 units 15 units 20 units 24 units 2 See answers Brainly User Brainly User I hope this helps you 24shazibas 24shazibas Answer: 12 units. Step-by-step explanation: took the test. New questions in Mathematics. Zo.om meeting id: 985-4147-9713 pass:KScT9a me and my friend are bored join if u want ages 11-16 ONLY

Thrust-specific fuel consumption – Wikipedia – From the CSS3 spec: [The ex unit is] equal to the used x-height of the first available font. The x-height is so called because it is often equal to the height of the lowercase "x". However, an 'ex' is defined even for fonts that do not contain an "x".x=7 72 divided by 6 sides (assuming the sides are of equal length) is 12 units per side. Because x+5 is the length of each side you can plug in 12 to get x+5=12 Solve to get 7.Transcript. Misc 5 Find the value of x for which x(𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂) is a unit vector.Let 𝑎 ⃗ = x(𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂) So, 𝑎 ⃗ = 𝑥𝑖 ̂ + 𝑥𝑗 ̂ + 𝑥𝑘 ̂ Given, 𝑎 ⃗ is a unit vector Magnitude of 𝑎 ⃗ is 1. What is the value of x? 12 units 15 units 20 units 24 – Thanks for the idea. I have implemented units in C# many different ways there always seems to be a catch. Now I can try one more time using the ideas discussed above. My goal is to be able to define new units based on existing ones like. Unit lbf = 4.44822162*N; Unit fps = feet/sec; Unit hp = 550*lbf*fpsWhat is the value of x? 12 units 15 units 20 units 25 units Need work shown please 2 See answers hi chloegayleen17 chloegayleen17 Answer: 15=x. Step-by-step explanation: a^2 + b^2=c^2 =9^2 +12^2 =x^2 =81 +144=x^2 =/225 =/x^2 =15=x. Where did you get 12^2 mathstudent55 mathstudent55 Answer:Standard units are a way of putting different kinds of observations on the same scale. The idea is to replace a datum by the number of standard deviations it is above the mean of the data. If a datum is above the mean, its value in standard units is positive; if it is below the mean, its value in standard units is negative.           