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Physics Question: In an experiment, one of the forces exerted on a proton is F =−αx^2(vec i), where α=12N/m^2.?

source : yahoo.com

Physics Question: In an experiment, one of the forces exerted on a proton is F =−αx^2(vec i), where α=12N/m^2.?

F = -12*x^2 i + 0 j

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How much work does vector F do when the proton moves along the straight-line path from the point (0.10m,0) to the point (0.10m,0.40m) ?

The force is only applied in the x direction (i) and the proton moved in the y direction (j). The force did no work. <—

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How much work does vector F do when the proton moves along the straight-line path from the point (0.10,0) to (0.3,0)?

Work = integral over the path(F*dx)

Work = integral over the path(-12*x^2 dx) ] from 0.1 to 0.3

Work = -4*x^3 ] 0.1 to 0.3

Work = -4*(.3^3 – .1^3) = -0.104 J

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How much work does vector F do when the proton moves along the straight-line path from the point

(0.3, 0) to (0.1,0)?

Opposite the previous answer

Work = 0.104 J

For the 2nd part, the force acts in the negative x direction and the movement is in the positive x direction, therefore energy is used from the system to work past the force, hence the negative sign.

In the 3rd part, the movement is now in the negative x direction, so the force adds energy to the system, hence the positive sign.

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Solved: In An Experiment, One Of The Forces Exerted On A P
Solved: In An Experiment, One Of The Forces Exerted On A P
Solved: In An Experiment, One Of The Forces Exerted On A P