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## Rewrite with only sin x and cos x. sin 3x I don’t know how to do this. Can you help me?

remember that

sin(a +b) = sin(a) cos(b) + sin(b) cos (a) call this #1

if a and b are both =x then sin (x + x) = 2sinx cosx call this #2

and cos2x = 1 – 2sin2x call this #3

sin(3x) =sinx (2x + x)

= sin2x cosx + sinx cos 2x using #1

= (2cosx sinx)(cos x) + sinx (1 – 2sin2x) using #2 and #3

=2cos2x sinx + sinx – 2sin3x

= your fourth choice

Solved: QUESTION 18 Rewrite With Only Sin X And Cos X. Sin – Answer to QUESTION 18 Rewrite with only sin x and cos x. sin 3x – cos 2x 2 sin x cos2 x – sin x + 2 sin3 x + 1 – 2 sin2x 2 sin x c…Rewrite the product as a sum. 2 \sin (5 x) \cos (3 x) Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉What I have so far: rewrite the problem as a product of two squared terms: $\sin^2(x)\sin^2(x)$ Apply the squared identity for sine twice: $(1+\cos(x)) (1-\cos(x)) (1+\cos(x)) (1-\cos(x))$

SOLVED:Rewrite the product as a sum. 2 \\sin (5 x) \\cos (3 x) – cos(3x) in terms of cos(x), write cos(3x) in terms of cos(x), using the angle sum formula and the double angle formulas, prove trig identities, verify trig i…cos 3x can be written using the sum and difference identity. cos (3x) = cos (2x + 1) cosx * cos2x – sinx * sin2x next, you have to use the double angle identities for both sine and cosine. there are three options for cosine, so choose one.the options are a. cos x – 4 cos x sin^2x b. -sin^3x + 2 sin x cos x c. -sin2x + 2 sin x cos x d. 2 sin2x cos x – 2 sin x cos x please help tell me what letter is your final answer

trigonometry – Rewrite $\sin^4 x$ so that it involves only – Question 1086857: Rewrite "sin 3x" with only sin x and cos x. OPTIONS: 2 sin x cos^2x + cos x 2 sin x cos^2x + sin^3x sin x cos^2x – sin^3x + cos^3x 2 cos^2x sin x + sin x – 2 sin^3x Answer by MathLover1(17842) (Show Source): You can put this solution on YOUR website! write as6. (2 points) Expand using an appropriate formula. Rewrite in terms of sin x and/or cos x only. (o,) sin 7 -X sin cos – cos sinx COS – singlsin(a +b) = sin(a) cos(b) + sin(b) cos (a) call this #1 if a and b are both =x then sin (x + x) = 2sinx cosx call this #2 and cos2x = 1 – 2sin2x call this #3 sin(3x) =sinx (2x + x)