source : yahoo.com

## what is the magnitude of the net torque on the system about the axle of the pulley?

a)

Torques on the axle

= 4 * 9.81 * 0.08 m-N

= 3.1392 m-N.

b)

Angular momentum of the system

= angular momentum of the counterweight + angular momentum of the pulley

L = [4 * w * (0.08)^2] + [2 * (0.08)^2 w] = 0.0384 w kgm^2/s

c)

Torque = dL/dt

=> 3.1392 = d/dt (0.0384 w)

=> dw/dt = 3.1392/0.0384 rad/s^2

=> angular acceleration, dw/dt = 81.75 rad/s^2

=> acceleration of the counterweight

= dw/dt * R

= 81.75 * 0.08 m/s^2

= 6.54 m/s^2.

(PDF) Force and torque of a string on a pulley – net force and the net torque on the pulley requires an integration of the inﬁnitesimal forces and. torques exerted on the pulley by each element of the magnitude of the friction force that prevents the string from slipping over the pulley?" does not. have a deﬁnite answer. As will be seen shortly…Show transcribed image text Calculate the net torque (magnitude and direction) on the beam in the figure below about the following axes. The 25 cm diameter disk in the figure can rotate on an axle through its center. What is the net torque about the axle? Express your answer using two significant…The speaker wire runs straight up from the speaker, over the pulley, and then horizontally across the table. She attaches the wire to the 4-kg amplifier on her tabletop, and then turns to get the other speaker. The table, however, is nearly frictionless, and the whole system begins to move when she…

(Get Answer) – Find the net torque on the wheel in the figure below… – The magnitude of the Earth's field is B=4.2e-05T. A penny is located at the outer edge of a disk (radius = 0.129 meter) that rotates about an axis perpendicular to the plane of the disk at its center.2. force exerted by the axle produce no torque about the rotation axis. Therefore, the net torque on. There is also an interesting question that, as far as we can tell, is never asked in the textbooks: What is the magnitude of the friction force that prevents the string from slipping on the pulley?If we consider the pulley and the string over it as one system such that the string does not slip then the net force acting is the difference in the tensions Could someone help me understand mathematically how do we calculate net torque on the pulley by considering pulley as the system i.e how is friction…

What is the net torque about the center of the pulley? – An axle passes through a pulley. Each end of the axle has a string that is tied to a support. Consider clockwise to be the positive direction of rotation, frictional effects from the axle are negligible, and the string wrapped around the The magnitude of the torque produced by force F is most nearly.I'm guessing that Ft is the force that is perpendicular to the radius. Is that what you mean? If so, that is the right equation. To give a longer answer than you might want, Torque = force x radius x sine of the angle between the force and the radius. In many cases, the angle is 90 degrees (it certainly is in your…If the pulley has radius R and moment of inertia I about its axle, determine the acceleration of the masses m1 and m2, and compare to the situation Making ACW positive (That is, I am guessing that this is the direction the system will go) the net torque is: tnet = RT1- RT2. Which is equal to Ia tnet…