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what is the magnitude of the net torque on the system about the axle of the pulley?

source : yahoo.com

what is the magnitude of the net torque on the system about the axle of the pulley?

a)

Torques on the axle

= 4 * 9.81 * 0.08 m-N

= 3.1392 m-N.

b)

Angular momentum of the system

= angular momentum of the counterweight + angular momentum of the pulley

L = [4 * w * (0.08)^2] + [2 * (0.08)^2 w] = 0.0384 w kgm^2/s

c)

Torque = dL/dt

=> 3.1392 = d/dt (0.0384 w)

=> dw/dt = 3.1392/0.0384 rad/s^2

=> angular acceleration, dw/dt = 81.75 rad/s^2

=> acceleration of the counterweight

= dw/dt * R

= 81.75 * 0.08 m/s^2

= 6.54 m/s^2.

(PDF) Force and torque of a string on a pulley

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(Get Answer) - Find the net torque on the wheel in the figure below...

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