## Which linear inequality is represented by the graph? y > 2x + 2 y ≥ x + 1 y > 2x + 1 y ≥ x + 2

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How to Find Equations of Tangent Lines and Normal Lines – $$ y – 2 = -3(x+1) $$. For reference, here's the graph of the function and the tangent line we just found. The procedure doesn't change when working with implicitly defined curves. Example 3. Suppose $$x^2 + y^2 = 16$$. Find the equation of the tangent line at $$x = 2$$ for $$y>0$$ .8x+5y=9;2y=-3x+4 solve the substitution method. tsi-upsx-rkuJoin H O R N YAND S E X Y GIRL. सरल कीजिए 4 2/7 +1 2/3. Choose the correct answer for the following questions:– 5×1=51. The zig-zag (or) tag line used to join the origin and given class interval while draw … ing the histogram is called as…The linear inequalities are given as follows: Calculation: First we will find the equation of the line. The line cuts the -axis on the coordinate as shown in the Therefore, the solution set of the line lie above the dotted line and it will represented by the symbol . Thus, the inequality satisfies the given graph.

which linear inequality is represented by the graph? – Brainly.in – Learn how to graph two-variable linear inequalities like y≤4x+3.y > 2x + 2. y ≥ x + 1. y > 2x + 1. Write an expression to represent the final cost of Ms. Morse's groceries, if the original cost is p.60 2(x + 2) in the diagram, gef and hef are congruent. what is the value of x? What are the end behaviors of f(x) = (x + 2)6?

Which linear inequality is represented by the graph? – Brainly.com – Ex 6.3, 15 Solve the following system of inequalities graphically: x + 2y ≤ 10, x + y ≥ 1, x – y ≤ 0, x ≥ 0, y ≥ 0 First Hence (10,0) does not lie in plane x > y So, we shade left side of line Also, given x ≥ 0, y ≥ 0 So, shaded region will lie in first quadrant Hence the shaded region represents the given inequality.Graph inequalities to solve linear programming problems. more… Plot the graphs of functions and their inverses by interchanging the roles of x and y. Find the relationship between the graph of a function and its inverse. Try plotting the circle with the equation in the form x2 + y2 = 52 see here]".Tangent lines problems and their solutions, using first derivatives, are presented. Problem 1. Find all points on the graph of y = x 3 – 3 x where the Solution to Problem 1: Lines that are parallel to the x axis have slope = 0. The slope of a tangent line to the graph of y = x 3 – 3 x is given by the first…

**Basic Absolute Value Function Translations: y=|x-h|+k** – Welcome to a video on

graphing translations of the basic absolute value function.

In this video, the equations will be in standard form with a equal to one. Standard form of an

absolute value function is y equals, or f of x equals

a times the absolute value of the quantity x minus h plus k. But again, for this

video, a is equal to one, and therefore the equations

will be in the form of y equals the absolute value of the quantity x minus h plus k. Before we discuss how h

and k affect the graph, there are a few things we should notice about the graph of the basic or parent absolute value function

shown here on the left. Remember, if we're ever not

sure how to make a graph, we can always make a table of

values to graph the function. Notice how the graph of

the absolute value function is a v shape, in this case it opens up. The lowest point on the graph, or the point where the

graph changes direction is this point here called the vertex. Notice how the vertex is at the origin, which has an ordered

pair, zero comma zero. Notice when x is greater than zero, or to the right of the vertex, the graph is linear with

a slope of positive one, meaning, if we start at any point on the graph on the right side and go up one and right one, we can determine another

point on the graph. And then, when x is less than zero, or to the left of the vertex,

the slope is negative one. Now, going back to the

form of the equation and y equals the absolute value of the quantity x minus h plus k, the value of h will shift

the graph left or right, and the value of k will

shift the graph up or down. When h is positive, or greater than zero, we would have the absolute

value of x minus h, so when we have subtraction here, h is positive, and the graph

is shifted right h units. And when h is less than zero, or negative, we would have the absolute

value of the quantity x minus negative h, which

simplifies to x plus h. So, when we have addition here, h is negative, and the

graph is shifted left the absolute value of h units. And now, for k, when k is

positive, or greater than zero, the graph is shifted up k units, and when k is less than zero, or negative, the graph is shifted down the

absolute value of k units. And then, finally, the vertex

is the ordered pair h comma k. Let's look at an animation

to better understand how the values of h and k affect the graph of the basic absolute value function. Let's first see how h affects

the graph of the function. Notice when h is positive, the graph is shifted right h units, and when h is negative,

the graph is shifted left the absolute value of h units. So if we stop here for a

moment, where h is negative six, let's determine the

equation of this graph. Well, if h is negative

six, and we know a is one and k is zero, this would

give us the equation y equals the absolute value of the quantity x minus negative six. Simplifying, we have the absolute value of the quantity x plus six. So again, when we have addition

inside the absolute value, the graph is shifted left,

in this case six units. And this should make

sense because notice how when x is negative six,

the ordered pair here, the vertex, is negative six comma zero, and notice when x is negative six, we do have a zero inside

the absolute value, the absolute value of zero is zero, and therefore the output, or y value, is zero when x is negative six. And when h is positive, let's

say when h is positive four, we would substitute

positive four in for h, which gives us the equation

y equals the absolute value of the quantity x minus four. Again, when we have subtraction

inside the absolute value, the graph is shifted right

in this case four units. And now let's see how k affects the graph. So we'll set h back to zero

and now change the value of k. Notice when k is positive, the

graph is shifted up k units, and when k is negative,

the graph is shifted down the absolute value of k units. So here, where k is

equal to negative four, because we have addition here, we normally don't write

plus negative four, we normally just write minus four. And we know a is one and h is zero, and therefore the equation

of this purple graph is y equals the absolute value

of x and then minus four. And let's take a look at an

equation when k is positive. Let's change k to a positive two. Notice how the graph is

shifted up two units, and because k is positive two, the equation of this purple

graph, or this graph here, is y equals the absolute

value of x plus two. Let's take a look at a few more examples. Let's say you were

asked to graph y equals, or g of x equals the absolute

value of x plus three. And again, because we have addition here, h is going to be negative three. We need to be thinking that

we can write x plus three as x minus negative three

to attermine the value of h, again, because in standard form, we do have subtraction

inside the absolute value. So, because h is negative three, the graph is shifted

left the absolute value of negative three or three units. And so notice how the graph

would be this orange graph here, where we have the parent graph, or basic absolute value

function graphed here in blue. We shift this left three

units to form the graph of y equals the absolute value

of the quantity x plus three. And then to graph y

equals the absolute value of x minus one, because

we have subtraction here, the graph is shifted right one unit because h is positive one. So again, the blue graph is the basic absolute value function. We would take this graph

and shift it right one unit to graph the given function. And now let's look at two more examples involving the value of k. If we want to graph y

equals the absolute value of x plus four, k is positive four, which means we shift the basic absolute value function up four units. So, in blue we have the basic

absolute value function. Because k is four, we shift

the graph up four units to graph the given function. And if we have y equals the

absolute value of x minus two, we shift the graph of the parent function, or the basic absolute value function, down two units to graph

the given function. So this is an overview of

how h and k affect the graph of the basic absolute value function. In the next video, we will

graph absolute value functions that have both the value

of h and k in the equation. I hope you found this helpful. .

**Solving Rational Inequalities** – .

**Find Quadratic Equation With Reciprocal Roots** – .