source : yahoo.com
Which substance is the reducing agent in this reaction?
Express your answer as a chemical formula.?
you have to leave a space now and then. Else YA will “…” your text as you can see above
2 KMnO4 + 3 Na2SO3 + H2O → 2 MnO2 + 3 Na2SO4 + 2 KOH
.. “reduction”.. quite literally means “reduction in oxidation state”
.. “oxidation”.. means the opposite.. “increase in oxidation state”
.. “agents” are opposites
looking at the balanced equation.
.. all K, O, H and Na remained unchanged in oxidation states.. (you verify this!)
.. Mn went from +7 in KMnO4 to +4 in MnO4
.. S went form +4 in Na2SO3 to +6 in Na2SO4
.. Mn went from +7 to +4…. Mn was REDUCED and is the OXIDIZING AGENT
.. S went from +4 to +6.. . …S was OXIDIZED and is the REDUCING AGENT
.. SOME instructors would say “S” is the reducing agent
.. SOME instructors would say “Na2SO3” is the reducing agent
I would probably say “S”.. the avoid the arguments
. (1) Na2SO3 is an ionic solid.. it’s really the SO3(2-) what was oxidized
. (2) is it the Na2SO3 or the Na2SO4 that was “oxidized”.. reactant or product
….. .or is it the SO3(-2) or SO4(-2) that is the “reducing agent”?
by stating “S” is the reducing agent, you avoid all that stuff.. but in this case since your instructor stated.. “enter the formula”.. I’m guessing he or she is of the “the entire compound not just the S” clan.
final answer… . Na2SO3
Which substance is the reducing agent in this reaction? – 2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH In a reaction, the reducing agent is the element or compound that donates electron or the one tht loses electrons. For this reaction KMnO4 is reduced into MnO2.Now the two half reactions can be combined just like two algebraic equations, with the arrow serving as the equals sign. The same species on opposite Unless otherwise noted, it does not matter if you add H2O or OH− as a source of O atoms, although a reaction may specify acidic solution or basic…2 KMnO4 (aq)+3 Na2SO3 (aq)+H2O (l)→2 MnO2 (s)+3 Na2SO4 (aq)+2 KOH (aq). Appearance: Purplish-bronze-gray needles | magenta-rose in solution ; Dark purple crystals. Na2SO3 – Sodium sulfite.
Balancing Redox Reactions – Introductory Chemistry – 1st Canadian… – The substances which act as reducing agent and oxidizing agent in the given redox reactions have to be identified. The substance which accepts electrons in a redox reaction is known as oxidizing agent. Hydrogen peroxide, oxygen are examples of oxidizing agent.The ion MnO4 is reduced toMnO2 and sulfur is oxidized to ion sulfate. Sulfite is the reducing agent. The reaction is the following: 4 KMnO4 + 4 KOH â†' 4 K2MnO4 + O2 + 2 2KMnO4 + 3H2SO4 = K2SO4 + 2MnSO4 + 3H2O + 2.5O2 (alkaline) and in other conditions……reduce and also identify oxidising agent and reducing agent in the following reaction Fe2O3+3CO gives 2Fe+3CO2 3MnO2+4Al gives 3Mn+2Al2O3 Always remember the substance being oxidised is reducing agent and vice versa. SO2 is reduced and is oxidising agent.
2 KMnO4 + 3 Na2SO3 + H2O 2 MnO2 + 3 Na2SO4 + 2 KOH… – No. In the MnO4- ion, the Mn has an oxidation state of +7. For it to act as a reducing agent, it needs to lose electrons to make another species gain them (so the oxidation state will at least move up to +8, OIL RIG=Oxidation is Loss, Reduction Is… In this reaction, KMnO4 acts as an oxidizing agent.2KMnO4 + 3Na2 SO3 + H2 O → 2MnO2 + 3Na2 SO4 + 2KOH Reducing agent in the above reaction shown is : A. K+. B. Answer. Reducing agent in the above reaction shown is SO32− ion as S atom itself is oxidized. The oxidation number of S increases…2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH. 2. The significance of category theory for philosophy 3. What is the deep. 1. Consider the overall reaction involving three elements as reactants, and a compound as the product.